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HEX -> Integer
Решение 1
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var i : integer
s : string;
begins := '$' + ThatHexString;
i := StrToInt(a);
end;
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Решение 2
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CONST HEX : ARRAY['A'..'F'] OF INTEGER = (10,11,12,13,14,15); VAR str : String; Int,
i : integer;
BEGINREADLN(str);
Int := 0;
FOR i := 1 TO Length(str) DO
IF str[i] < 'A' THEN Int := Int * 16 + ORD(str[i]) - 48
ELSE Int := Int * 16 + HEX[str[i]];
WRITELN(Int);
READLN;
END.
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